3u^2+7u=2

Solution for 3u^2+7u=2 equation:

3u^2+7u=2

We move all terms to the left:

3u^2+7u-(2)=0

a = 3; b = 7; c = -2;
Δ = b2-4ac
Δ = 72-4·3·(-2)
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{73}}{2*3}=\frac{-7-\sqrt{73}}{6}
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{73}}{2*3}=\frac{-7+\sqrt{73}}{6}
$